lightoj1078

maksyuki 发表于 oj 分类,标签:
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1078 - Integer Divisibility

For example you have to find a multiple of 3 which contains only 1's. Then the result is 3 because is 111 (3-digit) divisible by 3. Similarly if you are finding some multiple of 7 which contains only 3's then, the result is 6, because 333333 is divisible by 7.If an integer is not divisible by 2 or 5, some multiple of that number in decimal notation is a sequence of only a digit. Now you are given the number and the only allowable digit, you should report the number of digits of such multiple.

Input

Input starts with an integer T (≤ 300), denoting the number of test cases.

Each case will contain two integers n (0 < n ≤ 106 and n will not be divisible by 2 or 5) and the allowable digit (1 ≤ digit ≤ 9).

Output

For each case, print the case number and the number of digits of such multiple. If several solutions are there; report the minimum one.

Sample Input

Output for Sample Input

33 17 39901 1 Case 1: 3Case 2: 6Case 3: 12

 

题目类型:简单数学

算法分析:直接迭代计算temp = (10 * temp + k) % n直到temp == 0为止,输出迭代的次数即可,因为666 = 66 * 10 + 6,则有666 % n = (66 % n * 10 + 6 % n) % n