IP Address
Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1
Input
The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.
Output
The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.
Sample Input
4
00000000000000000000000000000000
00000011100000001111111111111111
11001011100001001110010110000000
01010000000100000000000000000001
Sample Output
0.0.0.0
3.128.255.255
203.132.229.128
80.16.0.1
Source
México and Central America 2004
题目类型：简单字符处理
算法分析：按照题目的要求将每8位的二进制数字转换为十进制，注意使用c语言中自带的库函数strtol，将base进制的数转换为十进制输出的数组中
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#include <cstdio> #include <iostream> #include <fstream> #include <cstdlib> using namespace std; int main() { int cases; //ifstream cin ("aaa.txt"); cin >> cases; while (cases--) { int i; for (i = 0; i < 4; i++) { char s[16]; int temp; scanf ("%8s", s); temp = strtol (s, 0, 2); if (i < 3) printf ("%d.", temp); else printf ("%d\n", temp); } } return 0; } |
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